How to use generic delegates as they are parameters of Extension Methods?

Yes I want tell you few things related to generic delegates;

Fun<TResult>()

Fun<T1,TResult>()

Fun<T1,T2,TResult>()

Fun<T1,T2,T3,TResult>()

All these all are generic delegates and these return types also delegate type.so maximum the return delegate are written by the complier.as per our T type  && as passing no’f parameters. This is greate.

 Why because we don’t need to write any delegates for each lamda expression.

The only thing is we have to write a good lamda expression.

Some of basic  delegates we seen with simple lamda expression now some complex type of delegate as a parameter we discuss now.

Fun<TResult>,Fun<int,TResult> we seen our example now below

Ex:
Func<bool, int, string>

  Func<bool, int, string> func2 = (b, x) =>

  string.Format("string = {0} and {1}", b, x);

  Console.WriteLine(func2.Invoke(true,10));

Then

Func<int, int, bool>

           int j1 =Convert.ToInt32(Console.ReadLine());

           int j2 = Convert.ToInt32(Console.ReadLine());

           Func<int, int, bool> fun3 = (j4, j8) => j1 == j2;

           Console.WriteLine(fun3.Invoke(j1, j2));

both j1 and j2 are equl then fun3 returns ---ture other with false

Func<int, int,int, bool>

                int j1 =Convert.ToInt32(Console.ReadLine());

           int j2 = Convert.ToInt32(Console.ReadLine());

           int j3 = Convert.ToInt32(Console.ReadLine());

       Func<int, int, int, bool> fun4 = (j10, j11, j12) => j3 == j1 + j2;

       Console.WriteLine(fun4.Invoke(14, 15, 16));

both j1 and j2 added value equl to j3.

menas 1,2,3----true  j1=1 j2=2 then j3=3 so true

these are good way to understand these parametrized delegates.


Note: Wherever we use generic delegate[lamda expression] there one anamous type will be created by complier implictly.


Note: a best way to know about these delegates and how annomous type use Refleactor tool.